Hello,
f(x)=x^3-11x²+40x-48
f(3)=3^3-11*3²+40*3-48=0
f(x)=(x-3)*(x-4)²
Answer D
I think you mean to say "hypotenuse". If so, then use the pythagorean theorem to get the following
a^2 + b^2 = c^2
16^2 + 20^2 = c^2
256 + 400 = c^2
656 = c^2
c^2 = 656
c = sqrt(656)
c = sqrt(16*41)
c = sqrt(16)*sqrt(41)
c = 4*sqrt(41)
The hypotenuse is exactly 4*sqrt(41) units long
This is approximately 25.612 when you use your calculator.
Answer:
About 425
Step-by-step explanation:
Tell me if you want the explanation.
Answer:
8274
Step-by-step explanation:
Answer:the 3rd one
Step-by-step explanation:
