Answer:
<em>π/2 and π/3</em>
Step-by-step explanation:
Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.
let P = cosx
The equation becomes 2P²-P = 0
P(2P-1) = 0
P = 0 and 2P-1 = 0
P= 0 and P = 1/2
Since P = cosx
cosx = 0 and cos(x) = 1/2
If cos(x) = 0
x = cos⁻¹0
x = 90⁰
x = π/2
If cos(x) = 1/2
x = cos⁻¹1/2
x = 60⁰
x = π/3
<em>Hence the solutions to the equation are π/2 and π/3.</em>
Look at it this way:
-- Since the two groups have the ratio of 4 to 7, then the first group has 4 parts
and the other group has 7 parts.
-- If the first group has 4 parts and the other group has 7 parts, then they have
11 parts all together.
-- Those 11 parts are all parts of 33. There must be ( 33 / 11 ) = 3 items in each part.
Now you can go back to the groups . . .
-- The first group has 4 parts.
With 3 items in each part, that's (4 x 3) = 12 items.
-- The other group has 7 parts.
With 3 items in each part, that's (7 x 3) = 21 items.
<span>40.4% I would say but if you need the whole problem I can give it to you.</span>
You’re answer is d (sum,sum).
