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4 years ago

Please solve question 1 for me

Mathematics

1 answer:

kozerog [31]4 years ago

5 0

Answer:

This is WAYYYYYYYYYYY too hard. You should ask ur teacher or friends. And parents.

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A particle moves along a line so that its velocity at time t is

Amanda [17]

Just trying to get my points up

6 0

3 years ago

Find the area of rectangle, where length is 15 cm and breadth is 7 cm.

Varvara68 [4.7K]

Question :-

Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

Area of Rectangle is 105 cm² .

$\rule {195pt} {2pt}$

Diagram :-

$\sf{15 \: cm} \\ \quad \quad \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\ \\ \\ \end{array}} \: \: \sf {7 \: cm}\end{gathered}\end{gathered}$

$\rule {195pt} {2pt}$

Solution :-

$\quad \quad$ » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

$\sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}$

Therefore , by Substituting the given values in the above Formula :-

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}$

Hence :-

Area of Rectangle = 105 cm² .

$\underline {\rule {195pt} {4pt}}$

Additional Information :-

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$

5 0

2 years ago

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Multiple 3/4 times 16/9

nataly862011 [7]

3/4 times 16/9 is equal to 1 1/3.

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3 years ago

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A recipe for sparkling grape juice calls for 1 1/2 quarts of sparkling water and 3/4 quart of grape juice. How much sparkling wa

Delicious77 [7]

Answer:

The amount of sparkling water that would be needed to mix with 9 quarts of grape juice is 18 quarts.

Ratio expresses the relationship between two or more numbers. It shows the frequency with which one value is contained in another value. According to the question, the ratio of sparkling water to grape juice is .

In order to determine the amount of sparkling water that would be needed with 9 quarts of grape juice, this equation would be used:

( × 9) ÷

( × 9) × = 18 quarts

To learn more about ratios, please check: brainly.com/question/17995727

Step-by-step explanation:

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3 years ago

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The speed of a stream is 4 mph. A boat travels 11 miles upstream in the same time it takes to travel 19 miles downstream. What i

Akimi4 [234]

Recall your d = rt, that is, distance = rate * time

now, bear in mind, that hmm, if say, the boat's speed in still water is say "r", when the boat is going upstream, is not really going at "r" speed, but the stream is subtracting from it, so is really going at " r - 4 " mph fast, since the speed rate of the stream is 4

now, when the boat is going downstream, is going "with" the stream, so is really going faster than "r", is actually going at " r + 4 " mph fast

now, the time it took upstream, is the same time it took downstream... say it took "t" time

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&11&r-4&t\\
downstream&19&r+4&t
\end{array}
\\\\\\

\begin{cases}
11=t(r-4)\implies \frac{11}{r-4}=\boxed{t}\\\\
19=t(r+4)\\
----------\\
19=\boxed{\frac{11}{r-4}}(r+4)
\end{cases}$

solve for "r"

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3 years ago