Just trying to get my points up
Question :-
- Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .
Answer :-
- Area of Rectangle is 105 cm² .

Diagram :-


Solution :-
» As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.
For calculating the Area of Rectangle , we will use the Formula :-
Therefore , by Substituting the given values in the above Formula :-



Hence :-
- Area of Rectangle = 105 cm² .

Additional Information :-
![\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bgathered%7D%5Cbegin%7Bgathered%7D%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%20%5C%5C%20%5Cunderline%7B%20%7B%20%5Ctextbf%20%7B%5Ctextsf%20%5Cred%7B%20%5Cdag%20%5C%3A%20%20%5C%3A%20More%20%5C%3A%20Formulas%20%5C%3A%20%20%5C%3A%20%20%5Cdag%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5Cfootnotesize%20%5Cbigstar%20%20%5C%3A%20%20%5Cbf%7BArea%20%5C%3A%20_%7BSquare%7D%20%3D%20Side%20%5Ctimes%20Side%7D%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%20%5Cfootnotesize%5Cbigstar%20%20%5C%3A%20%20%5Cbf%7BArea%20%5C%3A%20_%7BRectangle%7D%20%3D%20Lenght%20%5Ctimes%20Breadth%7D%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5Cfootnotesize%20%5Cbigstar%20%5C%3A%20%20%5Cbf%7BArea%20%5C%3A%20_%7BTriangle%7D%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20Base%20%5Ctimes%20Height%20%7D%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5Cfootnotesize%20%5Cbigstar%20%5C%3A%20%20%5Cbf%7BArea%20%5C%3A%20_%7BParallelogram%7D%20%3D%20Base%20%5Ctimes%20Height%7D%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5Cfootnotesize%20%5Cbigstar%20%5C%3A%20%20%5Cbf%7BArea%20%5C%3A%20_%7BTrapezium%7D%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5B%20%5C%3A%20A%20%2B%20B%20%5C%3A%20%5D%20%5Ctimes%20Height%20%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cfootnotesize%20%5Cbigstar%20%5C%3A%20%5Cbf%20%7BArea%20%5C%3A%20_%7BRhombus%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20Diagonal%20%5C%3A%201%20%5Ctimes%20Diagonal%20%5C%3A%202%7D%5Cend%7Barray%7D%7D%5Cend%7Bgathered%7D%5Cend%7Bgathered%7D%20)
3/4 times 16/9 is equal to 1 1/3.
Answer:
The amount of sparkling water that would be needed to mix with 9 quarts of grape juice is 18 quarts.
Ratio expresses the relationship between two or more numbers. It shows the frequency with which one value is contained in another value. According to the question, the ratio of sparkling water to grape juice is .
In order to determine the amount of sparkling water that would be needed with 9 quarts of grape juice, this equation would be used:
( × 9) ÷
( × 9) × = 18 quarts
To learn more about ratios, please check: brainly.com/question/17995727
Step-by-step explanation:
Recall your d = rt, that is, distance = rate * time
now, bear in mind, that hmm, if say, the boat's speed in still water is say "r", when the boat is going upstream, is not really going at "r" speed, but the stream is subtracting from it, so is really going at " r - 4 " mph fast, since the speed rate of the stream is 4
now, when the boat is going downstream, is going "with" the stream, so is really going faster than "r", is actually going at " r + 4 " mph fast
now, the time it took upstream, is the same time it took downstream... say it took "t" time
thus

solve for "r"