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igomit [66]
3 years ago
13

What is the complete factorization of the polynomial below x^3+x^2+4x+4?

Mathematics
2 answers:
Papessa [141]3 years ago
5 0
B. 

It can first be factored by splitting to:

(x + 1)(x^2 +4)

And (x^2 + 4) splits to x +/- 2i
vichka [17]3 years ago
3 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

x^3+x^2+4x+4

We need to given the complete factorization of the above expression.

So, First we factorise the above expression.

x^3+x^2+4x+4\\\\=x^2(x+1)+4(x+1)\\\\=(x+1)(x^2+4)

Since factorization of x^2+4 would contain complex number.

so, it becomes,

x^2+4=(x+2i)(x-2i)

So, the complete factorisation would be (x+2i)(x-2i)(x+1).

Hence, Option 'B' is correct.

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