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igomit [66]
4 years ago
13

What is the complete factorization of the polynomial below x^3+x^2+4x+4?

Mathematics
2 answers:
Papessa [141]4 years ago
5 0
B. 

It can first be factored by splitting to:

(x + 1)(x^2 +4)

And (x^2 + 4) splits to x +/- 2i
vichka [17]4 years ago
3 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

x^3+x^2+4x+4

We need to given the complete factorization of the above expression.

So, First we factorise the above expression.

x^3+x^2+4x+4\\\\=x^2(x+1)+4(x+1)\\\\=(x+1)(x^2+4)

Since factorization of x^2+4 would contain complex number.

so, it becomes,

x^2+4=(x+2i)(x-2i)

So, the complete factorisation would be (x+2i)(x-2i)(x+1).

Hence, Option 'B' is correct.

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What is the range of f(x) = 3/4x -4
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Answer:

The range is the resulting y-values we get after substituting all the possible x-values.

For the given function : f(x) = \frac{3}{4x} -4

<u>See the attached figure.</u>

The zeros of the denominator at x = 0

The domain is: (-∞,0)∪(0,∞)

<u>The range</u> of the function is the domain of the inverse function of f(x)

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The zeros of the inverse function:

4(y+4) = 0

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y = -4

∴ The range is (-∞,-4)∪(-4,∞)

So, the answer is {y | y > –4} ∪ {y | y < – 4}

=========================================

<u>Note</u>: If the given function is : f(x) = \frac{3}{4} x-4

It will be first degree polynomial function.

Both of the domain and the range = all real numbers R

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4 years ago
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