The line that passes through (0 1) and (1 4) is a linear equation
The equation of the points is y = 3x + 1
<h3>How to determine the equation of the points?</h3>
The points are given as:
(x,y) = (0 1) and (1 4)
Start by calculating the slope (m)
m = (y₂ - y₁)/(x₂ - x₁)
So, we have:
m = (4 - 1)/(1 - 0)
Evaluate
m = 3
The equation is then calculated as:
y = m(x - x₁) + y₁
This gives
y = 3(x - 0) + 1
Evaluate the product
y = 3x + 1
Hence, the equation of the points is y = 3x + 1
Read more about linear equations at:
brainly.com/question/1884491
Normally I'd love to help, but put in a picture. I'm confused.
Operations like +, - separates the terms.
Ex: 2x²+ 4yz-z
Answer:
1/10
Step-by-step explanation:
add 2/5 and 1/2 then subtract from 1 whole to find the remainder
make it so they have the same denominator
2/5 = 4/10
1/2 = 5/10
4/10 + 5/10 = 9/10
1=10/10
10/10-9/10 = 1/10
so 1/10 of the students don't exercise at all
