All categories

4 years ago

If m angle C is greater than the m angle E, then AB is

Mathematics

2 answers:

dangina [55]4 years ago

6 0

Answer:

Option B. Longer than

Step-by-step explanation:

In the figure attached it has been given that BC ≅ DE and AC ≅ FE

Now we have to tell the relation in sides AB and DF if ∠C > ∠E

Since two corresponding sides of these triangles are congruent and ∠C > ∠E, so opposite sides of the given triangles will be in the same ratio as angle are.

Therefore Option B) mAB > mDF will be the answer.

anygoal [31]4 years ago

3 0

Hello!

You answer is Longer than. You can see that the greater the angle of C, the longer AB will be than DF

Hope this helps :))

You might be interested in

Solve x:<br> 3 - x = -12<br> _ <br> 2<br> --Please help! Homework due in for Monday! Xx

Ivahew [28]

3/2 - x = -12

(multiply everything by 2 to get rid of fraction)

3-2x= -24

3+24 = 2x

3/2 + 12 = x

4 0

3 years ago

Quation x - = Whic<br> X-5/6=2/3

Harman [31]

X = 2/3 + 5/6 + 4/6 + 5/6 = 9/6 = 3/2

7 0

3 years ago

Justin wants to build a square garden in his backyard that will cover an area of 75 ft if tristan has 32 ft of material for the

statuscvo [17]

He does not have enough material

<h3>How to determine if he has enough material?</h3>

The given parameters are

Area = 75 square feet

Perimeter of material = 32 feet

Calculate the side length using

Length = Perimeter/4

So, we have

Length = 32/4

Evaluate

Length = 8

The area is

Area = 8^2

Evaluate

Area = 64

64 is less than 75

Hence, he does not have enough material

Read more about perimeters at

brainly.com/question/397857

#SPJ4

8 0

2 years ago

Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i

Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

$a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333$

So the correct answer is C, the area between the two functions is 4/3 units.

3 0

3 years ago

The length of a rectangle is 7 inches more than its width. If the perimeter of the rectangle is 66 inches, find the dimensions.

Igoryamba

Answer:

13 by 20 inches

Step-by-step explanation:

Represent the quantities as follows:

P = 2W + 2L

L = W + 7

Then P = 2W + 2(W + 7), or P = 4W + 14

and this formula has the value 66 inches.

Thus, P = 66 inches = 4W + 14 inches, or

52 inches = 4W

Dividing both sides by 4, we get W = 13 inches.

The width is 13 inches and the length is (13 + 7) inches, or 20 inches.

7 0

4 years ago