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3 years ago

How do I solve this?

Mathematics

1 answer:

valkas [14]3 years ago

7 0

If area multiply if perimeter are add

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What is 2.059 in expaned form using decimals

Harrizon [31]

2 + 0.5 + 0.09

Hope this helped ;)

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3 years ago

Solve the equation: 98= 3y - 4

lara [203]

Answer:

the answer is 34

Step-by-step explanation:

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3 years ago

Read 2 more answers

The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean $\mu$ , the actual temperature of the medium, and standard deviation $\sigma$ .

Let X be the random variable that represents the reading of the thermometer.

Confidence level : $=95\%$

We know that the z-value for 95% confidence interval is 1.96.

Then, we have

$-1.96$ $z=\dfrac{X-\mu}{\sigma}$

$\Rightarrow\ -1.96\sigma$

But all readings are within 0.6° of $\mu$ .

So, $1.96\sigma=0.6$

$\Rightarrow\ \sigma=\dfrac{0.6}{1.96}=0.30612244898\approx0.3061$

Hence, the required standard deviation will be

7 0

3 years ago

M u c h h e l p n e e d e d

ddd [48]

Answer:

Statements 2 and 3 are true

Step-by-step explanation:

Reading from the table

When x = -4, y = -1 so statement 1 is false

When x = -1, y = -2.5 so statement 2 is true

When x = 0, y = -3 so statement 1 is true

When x = 2, y = -4 so statement 2 is false

6 0

3 years ago

Gints

artcher [175]

Answer:

The correct statements are: B and D.

Step-by-step explanation:

Standard deviation is one of the measure of dispersion or spread of a dataset from the average value of the dataset. The standard deviation measures the variability of the distribution of values.

The higher the spread or variability in the data set, the greater is the standard deviation value and thus greater will be the magnitude of the deviance of the value from their average.

Then the standard deviation (S.D.) is given by,

$S.D.=\sqrt{\frac{1}{n-1}\sum\limits^{n}_{i=1} {(x_{i}-\bar x)^{2} }}$

The correct statements are:

B. It is a measure of variability.

D. It is calculated using the mean.

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4 years ago