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3 years ago

12

Which of the following ratios is NOT equivalent to 4/8

1 answer:

Serggg [28]3 years ago

4 0

B 2/4 on the top one

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How many solutions does this system of equations have?

8_murik_8 [283]

No solutions

if you substitute the equations into each other the x's and y's will cancel each other out and you will be left with 9=-6 which isn't true<span />

6 0

3 years ago

Which number is not equal to one of the following expressions? 2,500 × 10 250,000 ÷ 100 2,500 ÷ 10

ololo11 [35]

Answer:

2,500 ÷ 10

Step-by-step explanation:

Let's evaluate each expression one after the other and find out what they both gives us, then we'd now pick or select the one that doesn't give the required answer.

For 2,500 × 10

2500*10 = 25000

For 250,000 ÷ 10

250000/100= 25000

For 2,500 ÷ 10

2500/10= 250

So from the look of the results,

The one that gave us the odd result is

2,500 ÷ 10, and that's our answer.

4 0

3 years ago

There are 2.54 centimeters in an 1 inch. how many centimeters are 17 inches

Tpy6a [65]

43.18 would be your answer. :D

4 0

3 years ago

Read 2 more answers

When rabbits were introduced to the continent of Australia they quickly multiplied and spread across the continent since there w

Lady bird [3.3K]

Answer:

a. $y=6(1.7472)^x$

b. $y=6e^{0.558t}$

c.13.3 months

Step-by-step explanation:

a.-Given the first term at $t_0$ is 6 and the second term at $t_3$ is 32.

-Let's take rabbit population as a function of time to be

$y=ab^x$

where y is the population at time x and a the initial population at $t_0\\$

#We substitute our values to calculate the value of the constant b:

$y_x=ab^x\\\\y_3=ab^3\\\\32=6b^3\\\\b=1.472$

#Replace b in the population function:

$y=ab^x, b=1.7472,a=6\\\\\therefore y=6(1.7472)^x$

Hence, the regression for the rabbit population as a function of time x is $y=6(1.7472)^x$

b. The exponential function in terms of base $e$ is usually expressed as:

$A=A_0e^{kt}$

Where:

$A_0$ -is the initial population at $t_o$

$A$ -is the population at time t.

$k-$ is the exponential growth constant.

$e-$ the exponent

Our function in terms of base exponent is rewritten as:

$y=A_0e^{kt}$

#Substitute with actual figures to solve for t:

$y=A_0e^{kt}, y=32, xt=3, A_0=6\\\\32=6e^{3k}\\\\3k=In (32/6)\\\\k=0.5580$

Hence, the regression equation in terms of base e is $y=6e^{0.558t}$

c. We substitute y with any number higher than 10,000 to estimate the time for the rabbits to exceed 10,000.

-We know that $y=6e^{0.558t}.$

Therefore we calculate t as(take y=10001):

$y=6e^{0.558t}, y=10001\\\\10001=6e^{0.558t}\\\\1666.8333=e^{0.558t}\\\\0.558t= In 1666.8333\\\\t=13.2951$

Hence, it takes approximately 13.3 months for the population to exceed 10000

3 0

4 years ago

IMMEDIATE HELP PLS THANKS <33

Ksenya-84 [330]

Reflect across the y axis and moved through the translation x = 2

3 0

3 years ago