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3 years ago

Sally has a discount card that reduces the price of her grocery bill in a certain grocery by 5%

Mathematics

1 answer:

Wewaii [24]3 years ago

5 0

Whats The Question ?

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A The integer with the greatest value is the one that has the greatest absolute value.

pentagon [3]

Answer: B The integer with the greatest value is one that is farthest from zero on the number line.

Step-by-step explanation: hope it correct :D

5 0

3 years ago

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

Name the corresponding angle with angle 2

vaieri [72.5K]

Answer

3 it cant be 6 because lines L and M are not parallel

Step-by-step explanation:

5 0

3 years ago

Allison bought some shirts for her clothing store for $15 each. she received $50 off her entire purchase and spent a total of $4

Tom [10]

She Bought 23 shirts because if you do 400-50 you get 350 the / by 15 wich give you 23.333333ect

4 0

3 years ago

What is x? 6x-18+14x+38

evablogger [386]

Answer:

x= -1

Step-by-step explanation:

6x-18+14x+38

group= 20x+20

set equal to 0

20x+20=0

-20 -20

20x/20= -20/20

x= -1

8 0

3 years ago