(t-1)(t+1) = t^2-1 through the difference of squares rule
So,
(t-1)(t+1)(t^2+1)
(t^2-1)(t^2+1)
(x-1)(x+1) ... let x = t^2
x^2-1 .... another application of the difference of squares rule
(t^2)^2 - 1... plug in x = t^2
t^4 - 1
Answer:
x = 48°
Step-by-step explanation:
42 + 90 + x = 180 (we can tell because it is a straight line and straight lines are supplementary, ie = 180)
Rearrange the equation so that x is on one side:
x = 180 - 90 - 42
Simplify
x = 48°
Answer:
m=-4
y-intercept=8
x-intercept=2
Step-by-step explanation:
Please see attachment.
y-intercept=8
The y-intercept is where the line crosses the y-axis.
x-intercept=2
The x-intercept is where the line crosses the x-axis.
m=-4
If you do not know how to find slope by looking at graph, use slope formula.
(y2-y1)/(x2-x1)
Choose 2 points. You may use the x and y intercepts.
(2,0) and (0,8)
(8-0)/(0-2)=8/-2=-4
Hope this helps!
First of all we have to find the slope
y₂-y₁
--------- = m
x₂-x₁
0-2
------- = m
8-0
-2
---- = m
8
m = -¹/₄
y-y₁ = m (x-x₁)
y-2 = -¹/₄ (x-0)
y-2 = -¹/₄x
y = -¹/₄x + 2
CSHDJJDJSJSJDJSKSNSKSKSKSNSKSNHDJDIDJEEI