The value of the radius of T is 28 units
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How to determine the value of the radius of T</h3>
From the question, we understand that:
Segment AB is tangent to T at B
This means that
<ABT = 90
So, we have a right triangle
Let the radius of the triangle be r
By the Pythagoras theorem, we have
AT^2 = AB^2 + VT^2
This gives
(25 + r)^2 = 45^2 + r^2
Open the bracket
625 + 50r + r^2 = 2025 + r^2
Subtract r^2 from both sides of the equation
625 + 50r = 2025
Subtract 625 from both sides of the equation
50r = 1400
Divide both sides by 50
r = 28
Hence, the value of the radius of T is 28 units
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you draw a T. form and then you can start to in debit and credit
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-3.8
Step-by-step explanation:
-3.8+7.2=3.4
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Answer:
(c) 5x and 3x, and 4 and 1
Step-by-step explanation:
Like terms have the same variable(s) to the same power(s).
The terms of this expression are ...
- x^3: variable x, power 3
- 5x: variable x, power 1
- -3x: variable x, power 1
- 3y: variable y, power 1
- 4: no variable
- -1: no variable
The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.