A catering service offers appetizers, main courses, and desserts. A customer is to select appetizers, main courses, and desserts
for a banquet. In how many ways can this be done?
1 answer:
Answer:
6
Step-by-step explanation:
We have 3 items (n = 3),
Appetizers = A
Main course = M
Dessert = D
which can be ordered in 6 different ways. The problem is solved by thinking it as a permutation of 3 elements.
The formula for that is:
P = n!
P = 3! = 3 x 2 x 1 = 6
Let's see check it:
AMD
ADM
MAD
MDA
DMA
DAM
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Convert them into their simplest forms
20/12 = 10/6 = 5/3
25/15 = 5/3
So, they are equivalent
The answer is a
Hope it helps
2/5 = (2x2)/(5x2) = 4/10 = 0.4
The answer would be 3 and 2. Complementary means when you add two angles together, they equal 90° or a right angle.
Numbers greater than 5 are rounded up, and numbers 4 and lower are rounded down.
37.57 - This number is greater than 5 so we round up to 38.00 dollars.
