Which expression is equivalent to (3a)-2? O o 3a2 ܝ | ܝ

In a pile of coins there are 7 more quarters than nickels. If there is a total of$2.65 in coins, how many quarters are there?

Alinara [238K]

A quarter is equivalent to 25 cents or $0.25 and a nickel is equal to 5 cents or $0.05. In the given in this item, if there are x nickels then, there are x + 7 quarters. With these and the total amount known, we can now compute for the value of x.
(x)(0.05) + (x + 7)(0.25) = 2.65
Simplifying,
0.05x + 0.25x + 1.75 = 2.65
Simplifying further,
0.3x = 0.9
The value of x from the equation is 3. Hence, there are 10 quarters.

6 0

3 years ago

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For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a tot

sveta [45]

Answer:

the cost of 1 full price ticket is $9.5

Step-by-step explanation:

For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a total of $1235 the total sales both types of tickets were $2395

Let x be the number of full price tickets and y be the number of discount tickets

the theater sold 130 full-price ticket for a total of $1235 the total sales

130 full price tickets sold for $1235

the cost of 1 full price ticket is

$\frac{1235}{130}=9.5$

the cost of 1 full price ticket is $9.5

4 0

3 years ago

What is 0.987 tenths?

almond37 [142]

Answer:

0.0987

Step-by-step explanation:

6 0

3 years ago

The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

So

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

7 0

3 years ago

Compare the two functions in the table. Will the value of function y = 2x eventually exceed the value of function y = x10?

Andrew [12]

First we rewrite the functions:
y = 2x
y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
For x = 1 we have:
y = 2 (1) = 2
y = (1) ^ 10 = 1
We note that:
2> 1
Answer:
Yes, the value of function y = 2x eventually exceed the value of function y = x ^ 10.

5 0

3 years ago

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Which expression is equivalent to (3a)-2? O o 3a2 ܝ | ܝ | ܚ| ܘ ܩ|ܛܘ