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Vladimir [108]
3 years ago
8

Can someone check my work please?

Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
It would be better if u cud show the graph, but it sounds right
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Mrhopkins was making groups for the school field trip
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The points (-5, 6(<br><br> Hey
Vlad1618 [11]

Answer:

hi

Step-by-step explanation:

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An exponential function f(x)
natka813 [3]

Given:

An exponential function f(x)=ab^x passes through the points (0, 12000) and (2, 3000).

To find:

The values of a and b.

Solution:

We have,

f(x)=ab^x      ...(i)

It passes through the point (0,12000). Putting x=0 and f(x)=12000 in (i), we get

12000=ab^0

12000=a(1)

12000=a

Given function passes through the point (2,3000). Putting x=2, a=12000 and f(x)=3000 in (i), we get

3000=12000b^2

\dfrac{3000}{12000}=b^2

\dfrac{1}{4}=b^2

Taking square root on both sides.

\pm \dfrac{1}{2}=b

For an exponential function b cannot be negative. So, b=\dfrac{1}{2}.

Therefore, the value of a is 12000 and the value of b is \dfrac{1}{2}.

3 0
3 years ago
the book fair had a sale where 6 book were $20.46 if you wanted to buy 7 books ,how much money would you need ?
Rina8888 [55]

Answer:

$23.87

Step-by-step explanation:

Start by finding out how much one book costs-

$20.46/6=3.41

Then find out how much seven books cost- 3.41 (7)=$23.87

4 0
3 years ago
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Determine whether the three points are the vertices of a right triangle. (6, -6), (9, -6), (9, 1)
lisabon 2012 [21]

Answer:

The three given points are the vertices of a right triangle.

Step-by-step explanation:

To determine that the three points are the vertices of a right triangle let us find the distance between each two points

The formula of the distance is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = -6

∴ d_{1} = \sqrt{(9-6)^{2}+(-6--6)^{2}}=\sqrt{9+0}

∴ d_{1} = 3

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = 1

∴ d_{2} = \sqrt{(9-6)^{2}+(1--6)^{2}}=\sqrt{9+49}

∴ d_{2} = \sqrt{58}

∵ x_{1} = 9 and y_{1} = 1

∵ x_{2} = 9 and y_{2} = -6

∴ d_{3} = \sqrt{(9-9)^{2}+(-6-1)^{2}}=\sqrt{0+49}

∴ d_{3} = 7

<em>Let us use the fact that if the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side</em>

∵ The longest side is \sqrt{58}

∵ The other two sides are 3 and 7

∵ ( \sqrt{58} )² = 58

∵ (3)² + (7)² = 9 + 49 = 58

∴  ( \sqrt{58} )² = (3)² + (7)²

- By using the fact above

∴ The triangle is a right triangle

The three given points are the vertices of a right triangle.

8 0
4 years ago
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