Answer:
Step-by-step explanation:
P = 5x
P = 5(3) = 15
Multiplying both sides by 
gives
so that substituting 
and hence 
gives the linear ODE,
Now multiply both sides by 
to get
so that the left side condenses into the derivative of a product.
![\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E3v%5D%3D3x%5E2)
Integrate both sides, then solve for 
, then for 
:
![\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%5Csqrt%5B3%5D%7B1%2B%5Cdfrac%20C%7Bx%5E3%7D%7D%7D)
Answer:
(√2)/2
Step-by-step explanation:
The ratio of the radius of the circle to the side of the inscribed square is the same regardless of the size of the objects.
The radius of the circle is half the length of the diagonal of the square. For simplicity, we can call the side of the square 1, so its diagonal is √(1²+1²) = √2 by the Pythagorean theorem. The radius is half that value, so is (√2)/2. The desired ratio is this value divided by 1.
Scaling up our unit square to one with a side length of 3 inches, we have ...
radius/side = ((3√2)/2) / 3 = (√2)/2
_____
A square with a side length of 3 inches will have an area of (3 in)² = 9 in².
126.4 I guess.... How you wrote it is a tad confusing. Is the second set of numbers another question?
