Answer:
1. 2588672 bits
2. 4308992 bits
3. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Explanation:
1. Number of bits in the first cache
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits
2. Number of bits in the Cache with 16 word blocks
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits
3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Answer:
IF THIS DOES OCCUR THEN THE SYSTEM WILL AUTOMATICALLY CUT OFF WITH NO WARNING AT ALL...
Explanation:
ON WHAT INFORMATION AND RESEARCH HAS GIVEN ME IT WILL BE THE AWNSER GIVEN AT THE TOP...
Answer:
Option A i.e., SME for further investigation.
Explanation:
Following the reports of such a security incident into an SOC, an incident respondent examines the incident but could not determine the cause of that same incident as well as establish an appropriate response protocol. The ticket for an incident must be applied to SME for even more inquiry. So, the following answer is correct.
Answer:
True
Explanation:
There are many form a quick editing
i hoped this helped
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