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2 years ago

Find sin q if q is an angle in standard position and the point with coordinates (4, 3) lies on the terminal side of the angle.

1 answer:

4 0

Letâ€™s say we have a starting point (0,0), the point (4,3) are distance apart at 90 degrees, hence the hypotenuse to those two distance will be 5. Therefore sin q = 4/5.

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The length of a swimming pool is 8m longer than its width and the area is 1o5m2?

Nina [5.8K]

Let the breadth be x
length=x+8
according to the question
area of the pool = l*b
105=x*x+8
if u solve this equation further u will get the answer

5 0

3 years ago

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

2 years ago

Use a graph to describe the domain and range of each of the functional sequence below

Y_Kistochka [10]

Answer:

ℝ

Step-by-step explanation:

All linear functions have a range and domain of all real numbers.

I am joyous to assist you anytime.

8 0

2 years ago

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

Alecsey [184]

Answer:

y^2 = 28x

Step-by-step explanation:

Since the directrix is horizontal, use the equation of a parabola that opens left or right.

(y−k)^2 = 4p(x−h)

Find the vertex.

(0,0)

Find the distance from the focus to the vertex.

p = 7

Substitute in the known values for the variables into the equation

(y−k)^2 = 4p(x−h).

(y−0)^2 = 4(7)(x−0)

Simplify.

y^2 = 28x

7 0

3 years ago

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-3 ¼ divided by -1/8

Marat540 [252]

Answer:

The answer is 26

Step-by-step explanation:

4 0

3 years ago

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