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Lesechka [4]
2 years ago
15

If f(x) = 5x - 4 and g(x) = x2, what is (gºf)(2)?

Mathematics
2 answers:
Alex787 [66]2 years ago
6 0

Answer:

Step-by-step explanation:

(g•f)(2) = g(f(2))

Since f(x) = 5x - 4

f(2) = 5(2) - 4 = 10 - 4 = 6

(g•f)(2) = g(f(2))

g(f(2)) = g(6) = (6)^2 = 36

yulyashka [42]2 years ago
3 0

Step-by-step explanation:

  • set F function in g function:

gof(x) = (5x-4)2

  • simplified:

gof(x) = 10x-8

  • put 2 in function

gof(2) = 10(2) - 8 => 20-8 => 12

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Urgent, please help! Will give points and brainliest answer
Korvikt [17]

Answer:

Step-by-step explanation:

The attached photo contains the Venn diagram with the circles representing the set of Spa's, fitness clubs and children clubs

The total number of resorts was 110

a) the number of the resorts that had only Spa is

33 - (2 + 8 + 9) = 14

b)the number of the resorts that had exactly one of these features is

Exactly Spa is 33 - (2 + 8 + 9) = 14

Exactly fitness center is 67 - (15 + 8 + 9) = 35

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14 + 35 + 20 = 69

c) the number of the resorts had at least one of these features would be

(14 + 35 + 20 + 2 + 15 + 9 + 8) = 103

d) the number of the resorts had exactly 2 of these features would be

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e) the number of the resorts that none of these features would be

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3 years ago
How wide is a rectangular strip of land with the length 3/4 mile and area 1/2 square mile?
antiseptic1488 [7]
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3 years ago
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How do I solve this?
Pavlova-9 [17]
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What od linear algebra exactly?
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<h3>mark me a brainlist</h3>

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2 years ago
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
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3 years ago
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