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AVprozaik [17]
3 years ago
6

James wants to go to a concert with his friends. The tickets to the show cost $10 each. If James buys x tickets at a cost of c d

ollars, represent c as a function of x.
Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

C = f(x)=10x

Step-by-step explanation:

plato answer

faltersainse [42]3 years ago
7 0
Is there a graph for this?
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1. Bill decided to buy six books on history instead
bulgar [2K]

Answer: 2/3 books on politics

Step-by-step explanation:

The opportunity cost of something is the next best alternative that you would have taken if you did not instead go for the option that you took.

Opportunity cost here is the number of books on politics that Bill had to give up to get a single book on history.

= Number of politics books / Number of history  books

= 4 / 6

= 2/3 books on politics

<em>Bill gave up 2/3 books on politics to get a single history book. </em>

6 0
3 years ago
What is the volume of this container
Svetllana [295]

Answer: 504

Step-by-step explanation:

3 0
3 years ago
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Place the numbers in order from greatest to least.90.9890.08990.989.8990
padilas [110]

EXPLANATION:

The decimal number that is greater is the one with the largest integer part. If they have the same integer part, the first different decimal place is compared.

Now we are going to order the numbers of the exercise,

The correct order is:

-90.98

-90.9

-90.089

-90

-89.89

6 0
1 year ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
denis-greek [22]
You have to use trigonometry
8 0
3 years ago
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A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work
lubasha [3.4K]

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = \frac{1}{4} = 0.25

Probability that he drives the large car = P(L) = \frac{3}{4} = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5

Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So,    P(S / WT)  =  \frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}

                          =  \frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}

                          =  \frac{0.175}{0.55}

                          =  <u>0.318</u>

Hence, the required probability is 0.318.

8 0
3 years ago
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