Please help! (I cant figure out)

The steps.txt file contains the number of steps a person has taken each day for a year. There are 365 lines in the file, and eac

Bumek [7]

Answer:

In Python:

file = open('steps.txt', 'r')

readLine = file.readlines()

begin = 0

mdays = (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)

print("Month"+"\t\t"+"Average Steps")

for m in range(len(mdays)):

end = begin + mdays[m]

steps = readLine[begin:end]

sumsteps = 0

for s in steps:

sumsteps = sumsteps + int(s)

average = round(sumsteps/mdays[m],1)

print(str(m+1)+"\t\t"+str(average))

begin = begin + mdays[m]

Explanation:

This line opens the step.txt file

file = open('steps.txt', 'r')

This reads the content of the file

readLine = file.readlines()

begin = 0

This initializes the months of the days to a tuple

Mmdays = (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)

This prints the header

print("Month"+"\t\t"+"Average Steps")

This iterates through the tuple

for m in range(len(Mmdays)):

This calculates the days in each month

end = begin + Mmdays[m]

This gets the number of steps in each month

steps = readLine[begin:end]

This initializes the number of steps to 0

sumsteps = 0

This iteration sums up the number of steps in each month

for s in steps:

sumsteps = sumsteps + int(s)

This calculates the average of steps rounded to 1 decimal place

average = round(sumsteps/Mmdays[m],1)

This prints the calculated average

print(str(m+1)+"\t\t"+str(average))

This calculates the beginning of the new month

begin = begin + Mmdays[m]

8 0

3 years ago

Which type of error is a random error

zlopas [31]

Answer:

statistical fluctuations

Explanation:

8 0

3 years ago

Read 2 more answers

You manage a small LAN for a branch office. The branch office has three file servers and few client workstations. You want to us

lana66690 [7]

You manage small LAN for a branch office. The branch office has three file servers and few client workstations. You want to use Ethernet device and offer guaranteed bandwidth to each server. You design the network by connecting all network devices to a switch. Connect each server to its own switch port.

Explanation:

A local-area network (LAN) is a computer network that spans a relatively small area.
Most often, a LAN is confined to a single room, building or group of buildings, however, one LAN can be connected to other LANs over any distance via telephone lines and radio waves.
The LAN is the networking infrastructure that provides access to network communication services and resources for end users and devices spread over a single floor or building.
Designing a LAN for the campus use case is not a one-design-fits-all proposition.
If there is a single 48-port switch, 47 devices can be supported, with only one port used to connect the switch to the rest of the network, and only one power outlet needed to accommodate the single switch

8 0

3 years ago

(Display four patterns using loops) Ask the user to enter an integer to

fomenos

Answer:

Hi There was small mistake. It is working fine for me. When you run from command line - use LoopPattern, not looppatern

import java.util.Scanner;

public class Looppattern {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.println("Enter how man levels you need: ");

int levels = sc.nextInt();

System.out.println("\n---------------Pattern A-----------------\n");

for (int p = 1; p <= levels; p++) {

for (int k = 1; k <= p; k++) { // increasing each level printing

System.out.print(k);

}

System.out.println();

}

System.out.println("\n---------------Pattern B-----------------\n");

int r = levels;

for (int p = 1; p <= levels; p++) {

for (int k = 1; k <= r; k++) {

System.out.print(k);

}

r--; // decreasing levels

System.out.println();

}

System.out.println("\n---------------Pattern C-----------------\n");

for (int p = 1; p <= levels; p++) { // here incresing

for (int k = p; k > 0; k--) { // and here decreasing pattern to

// achieve our required pattern

System.out.print(k);

}

System.out.println();

}

System.out.println("\n---------------Pattern D-----------------\n");

r = levels;

for (int p = 1; p <= levels; p++) {

for (int k = 1; k <= r; k++) {

System.out.print(k);

}

r--; // decreasing levels

System.out.println();

}

Explanation:

4 0

3 years ago

In Microsoft word you can access the blank command from the mini toolbar

Softa [21]

Your answer would be:

In Microsoft Word you can access the insert citation command from the mini toolbar.

3 0

3 years ago