What would happen if computers only had input peripherals and a CPU?
1 answer:
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Answer:
Explanation:
The following Python code creates all of the necessary functions in order to request and validate all of the inputs from the user. Once everything is entered and validated it calculates the total fee and outputs it to the user. Also calls the entire class at the end using a test variable...
class Customer:
library_card = 0
patrons_name = ""
patrons_address = ""
type_of_book = ""
book_title = ""
days_overdue = 0
fee = 0.0
book_list = ['paperback regular', 'paperback best seller', 'magazine', 'hardcover']
def __init__(self):
self.library_card = self.get_library_card()
self.patrons_address = input("Patron's Address: ")
self.book_title = input("Book Title: ")
self.type_of_book = self.get_type_of_book()
self.days_overdue = float(self.get_days_overdue())
self.calculate_total()
print("Your total Fee is: " + str(self.fee))
def get_library_card(self):
library_card = int(input("Enter 4-digit library card number: "))
if (type(library_card) == type(0)) and (len(str(library_card)) == 4):
return library_card
else:
print("Invalid Card number:")
self.get_library_card()
def get_type_of_book(self):
type_of_book = input("Type of Book 1-4: ")
if (int(type_of_book) > 0) and (int(type_of_book) <= 4):
return int(type_of_book)
else:
print("Invalid Type")
self.get_type_of_book()
def get_days_overdue(self):
days_overdue = input("Number of Days Overdue: ")
if int(days_overdue) >= 0:
return days_overdue
else:
print("Invalid number of days")
self.get_days_overdue()
def calculate_total(self):
if self.type_of_book == 1:
self.fee = 0.20 * self.days_overdue
if self.fee > 8:
self.fee = 8
elif self.type_of_book == 2:
self.fee = 0.50 * self.days_overdue
if self.fee > 15:
self.fee = 15
elif self.type_of_book == 3:
self.fee = 0.25 * self.days_overdue
if self.fee > 5:
self.fee = 5
else:
self.fee = 0.30 * self.days_overdue
if self.fee > 23:
self.fee = 23
test = Customer()
Answer:
Here is the JAVA program:
import java.util.Scanner; //to accept input from user
public class Main { // class name
public static void main(String [] args) { // start of main method
Scanner input = new Scanner(System.in); // creates Scanner class object to take input from user
System.out.println("Please Enter the Cost of the Item: "); // prompts user to enter the cost of item
double itemCost = input.nextDouble(); //scans and reads the input value of item cost
System.out.println("Please Enter the Amount Paid: "); // prompts user to enter the amount paid
double amount = input.nextDouble(); //scans and reads the value of amount from user
int change = (int)(amount * 100 - itemCost * 100); //compute the remaining amount i.e. change
System.out.println("Change Owed: " + change / 100.0); // displays the owed change
int quarters = change / 25; // computes the value for quarters
change = change % 25; // compute the quarters remaining
int dimes = change / 10; // computes dimes
change = change % 10; // computes dimes remaining
int nickels = change / 5; // computes nickels
change = change % 5; // compute nickels remaining
int pennies = change; // computes pennies
System.out.println("Quarters: " + quarters); // displays computed value of quarters
System.out.println("Dimes: " + dimes); // displays value of dimes
System.out.println("Nickels: " + nickels); // displays value of nickels
System.out.println("Pennies: " + pennies); }} //displays value of pennies
Explanation:
I will explain the program with an examples.
Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:
Change is computed as
change = (int)(amount * 100 - itemCost * 100);
This becomes;
change = (int)(5.00 * 100 - 4.57 * 100)
= 500 - 457
change = 43
Now the change owed is computed as:
change / 100.0 = 43/100.0 = 0.43
Hence change owed = 0.43
Next quarters are computed as:
quarters = change / 25;
This becomes:
quarters = 43/25
quarters = 1
Now the remaining is computed as:
change = change % 25;
This becomes:
change = 43 % 25;
change = 18
Next the dimes are computed from remaining value of change as:
dimes = change / 10;
dimes = 18 / 10
dimes = 1
Now the remaining is computed as:
change = change % 10;
This becomes:
change = 18 % 10
change = 8
Next the nickels are computed from remaining value of change as:
nickels = change / 5;
nickels = 8 / 5
nickels = 1
Now the remaining is computed as:
change = change % 5;
This becomes:
change = 8 % 5
change = 3
At last the pennies are computed as:
pennies = change;
pennies = 3
So the output of the entire program is:
Change Owed: 0.43 Quarters: 1 Dimes: 1 Nickels: 1 Pennies: 3
The screenshot of the output is attached.
