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il63 [147K]
2 years ago
13

What would happen if computers only had input peripherals and a CPU?

Computers and Technology
1 answer:
lisov135 [29]2 years ago
3 0
Then there would be no way to see the output based off what you input. =)
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Credible sites contain __________ information,
Reptile [31]

Answer:

All of the above. Explanation:Credible sites include the date of any information, cite the source of the information presented, are well designed and professional.

6 0
2 years ago
Read 2 more answers
The area of a rectangle is the rectangle's length times its width.
aliya0001 [1]

Answer:

Following are program to this question:

#include <iostream> //defining header file  

using namespace std;  

int main() //defining main method

{

   double len1,len2,wid1,wid2,area1,area2; //defining double variable

   cout << "Enter first rectangle length: "; //print message

   cin >> len1;//input first rectangle length value

   cout << "Enter first rectangle width: ";//print message

   cin >> wid1; //input first rectangle width value

   area1 = len1*wid1; //calculate area and holds its value  

   cout << "Enter second rectangle length: ";//print message

   cin >> len2; //input second rectangle length value

   cout << "Enter second rectangle width: ";//print message

   cin >> wid2; //input second rectangle width value

   area2 = len2*wid2; //calculate area and holds its value  

   if(area1 > area2) //check condition area1 value is greater then area2

   {

    cout << "First rectangle area value is greater";//print message

   }

   else if(area2 > area1)//check condition area2 value is greater then area1

   {

       cout << "Second rectangle area value is greater";//print message

   }

   else //else block

   {

       cout << "both rectangle area is same";//print message

   }

   return 0;

}

Output:

Enter first rectangle length: 3

Enter first rectangle width: 5

Enter second rectangle length: 5

Enter second rectangle width: 3

both rectangle area is same

Explanation:

The description of the above program can be described as follows:

  • In the given code, the double variable is declared, which is "len1, len2, wid1, wid2, area1, and area2". In the next line, a message is a print, that accepts "len1 and wid1" value in the next line, the area variable is used that calculates area1.
  • In the next step, the "len2 and wid2"  variable is used, that accepts values and calculates its area, and in the next line, the conditional statement is used that checks its value.
  • In the if the block it uses both area1 and area2 value, that checks area1 is greater then area2, it is will print first rectangle area is greater.  
  • Otherwise, it will go to else if block, that checks area2 is greater then area1, it is will print second rectangle area is greater.  In the else section, it will print both equal areas.

4 0
3 years ago
Which of the following is a useful policy to minimize waste and mistakes?
anastassius [24]

Answer:

Option C

Explanation:

To ensure correct input data, proper  procedure is must in order to minimize waste and mistakes.

5 0
2 years ago
You have to calculate the total amount you spent at the mall today. Which function should you use to do so?
rosijanka [135]
If it has to be exactly then C-sum
3 0
3 years ago
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4. In this problem, we consider sending real-time voice from Host A to Host B over a packet-switchednetwork (VoIP). Host A conve
mina [271]

Answer:

The time elapsed is 0.017224 s

Solution:

As per the question:

Analog signal to digital bit stream conversion by Host A =64 kbps

Byte packets obtained by Host A = 56 bytes

Rate of transmission = 2 Mbps

Propagation delay = 10 ms = 0.01 s

Now,

Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.

Time taken to generate and convert all the bits into digital signal is given by;

t = \frac{Total\ No.\ of\ packets}{A/D\ bit\ stream\ conversion}

t = \frac{56\times 8}{64\times 10^{3}}          (Since, 1 byte = 8 bits)

t = 7 ms = 0.007 s

Time Required for transmission of the packet, t':

t' = \frac{Total\ No.\ of\ packets}{Transmission\ rate}

t' = \frac{56\times 8}{2\times 10^{6}} = 2.24\times 10^{- 4} s

Now, the time elapse between the bit creation and its decoding is given by:

t + t'  + propagation delay= 0.007 + 2.24\times 10^{- 4} s + 0.01= 0.017224 s

8 0
2 years ago
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