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Citrus2011 [14]
3 years ago
6

What is the value of x in 2x+8+3x+5=123

Mathematics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

5x + 13 = 123

     - 13   - 13

5x = 110

5x/5 = 110/5

x = 22

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1. Each kid eats the same amount of food each morning.
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Answer:

a) One kid eat tubs of yogurt = 1.3 tub of yogurt

b) One kid eat granola = 3.33 ounces

c) cost to feed one kid each morning is $1.12

Step-by-step explanation:

Three kids eat tubs of yogurt = 4

Three kids eat granola = 10 ounces

Cost of one tub of yogurt = 54 cents

Cost of 10 ounces of cereal = $1.26

a) One kid eats how many tubs of yogurt in a morning?

Three kids eat tubs of yogurt = 4

One kid eat tubs of yogurt = 4/3

                                            = 1.3 tub of yogurt

b) How many ounces of granola does a kid eat each morning?

Three kids eat granola = 10 ounces

One kid eat granola = 10/3

                                  = 3.33 ounces

c) How much does it cost to feed one kid each morning?

Cost of 1 tub of yogurt = 54 cents

Cost of 1.3 tub of yogurt = 54*1.3 = 70.2 cents

Converting cents to dollar:

100 cents = 1 dollar

70.2 cents = $0.7

So, Cost of 1.3 tub of yogurt (for one kid)= $0.7

Cost of 10 ounces of cereal = 1.26

Cost of 1 ounce of cereal = 1.26/10

Cost of 3.33 ounces of cereal = (1.26/10)*3.33

                                                 = $0.42

Cost of 3.33 ounces of cereal (for one kid) = $0.42

Total cost for each kid = $0.42+$0.7 = $1.12

So, cost to feed one kid each morning is $1.12

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Subtract 5 from 1/3 of 23
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2 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

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2 years ago
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