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ankoles [38]
1 year ago
12

Joaquin wants to make his famous chocolate chip cookies to bring to his friend's birthday party. The original recipe serves 8 pe

ople and requires 1/2 of a cup of butter but he
needs it to serve 28 people. How many cups of butter will he need?
Mathematics
1 answer:
Valentin [98]1 year ago
3 0

Answer: He will need 1 1/4 cups of butter

Step-by-step explanation:

1. We can do 28/8 to find how much we need to multiply our 1/2 cup of butter to keep the ratio of people to cups of butter the same. 28/8= 3 1/2

2. Then we can multiply 3 1/2 and 1/2 to get 1 1/4 cups of butter.

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Find the missing number to make these fractions equal.<br><br> 3/4 = ?/8
babymother [125]

The answer is 6, reaosn is because 6/8 is not simplified, so if we divide both sides by 2 (the numerator and the denominator), we can get a simplified fraction, which is 3/4. Steps: 6/8, 6 divided by 2/8 divided by 2, 3/4.

Hope this helped!

Nate

7 0
3 years ago
Solve for x. MUST SHOW ALL WORK TO RECEIVE FULL CREDIT! (See picture for equation)
ioda
\frac{x}{2.4} = \frac{3}{8}

For proportions and to find x we have to cross multiply
8 × (x) = 3 × 2.4

8x = 7.2
Divide by 8 to isolate x

\frac{8x}{8} =  \frac{7.2}{8}
8 and 8 cancels out

x = 0.9
5 0
3 years ago
Read 2 more answers
javon is helping his dad build a tree house. he has a piece of trim that is 13 ft long. how many pieces can Javon cut that are 1
wel
Well a yard is 3 ft
so  divide 3 into 13
3 goes into 13 4 times and you get 12
you have 4 whole yards and 1 ft left or 1/3 of a yard.
:) hoped this helped

6 0
3 years ago
Read 2 more answers
Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati
Brrunno [24]
Remember that <span>an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.
 
Lets solve our equation to find out what is the extraneous solution:
</span>\sqrt{x-3} =x-5
(\sqrt{x-3})^2 =(x-5)^2
x-3=x^2-10x+25
x^2-11x+28=0
(x-4)(x-7)=0
x-4=0 and x-7=0
x=4 and x=7
<span>
So, the solutions of our equation are </span>x=4 and x=7. Lets replace each solution in our original equation to check if they are valid solutions:
- For x=7
\sqrt{x-3} =x-5
\sqrt{7-3} =7-5
\sqrt{4} =2
2=2
We can conclude that 7 is a valid solution of the equation.

- For x=4
\sqrt{x-3} =x-5
\sqrt{4-3} =4-5
\sqrt{1} =1
1 \neq 1
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: <span>D. the extraneous solution is x = 4</span>
7 0
3 years ago
Stephanie had 22 marbles. she gave maggie and sam each 4 marbles. explain how you can find how many marbles stephanie has left?
Lina20 [59]
She had 22 marbles and gave away, 4 to two people, so 4*2 = 8. 22-8=14. she has 14 marbles left.
4 0
3 years ago
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