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dalvyx [7]
3 years ago
9

WILL MARK BRAINLIEST! identify the equation in point slope form

Mathematics
1 answer:
AURORKA [14]3 years ago
4 0
The answer is C. The formula for point slope for is y- y1 = m(x - x1). y-(-2) = 1/2(x-(-3). This is rewritten as y + 2 = 1/2(x + 3)
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What is different about the normality requirement for a confidence interval estimate of sigma and the normality requirement for
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Answer:

The normality requirement for a confidence interval estimate of sigma is (stricter) than the normality requirement for a confidence interval estimate of mu. Departures from normality have a (greater) effect on confidence interval estimates of sigma than on confidence interval estimates of mu. That is, a confidence interval estimate of sigma is (less)

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9. The ratio of boys to girls in Mrs. Reeves's class is 4 to 5. There are 20 girls in the
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Answer:

boys : girls

4 : 5

multiply by 4

16 : 20

<u>total = 36</u>

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Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

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How would you represent a situation that has more than 1 solution? What does the solution represent about that situation? Explai
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Answer:

You don't

Step-by-step explanation:

For starters there is only one answer to every math question if you get an answer make sure it is correct

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im try ing to think

Step-by-step explanation:

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