// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
Answer:
Big data are used to _____. Select 3 options.
understand people’s hobbies
analyze people’s interests
make decisions about marketing
Explanation:
100%
The answer is a. im pretty positive but if im wrong super sorry
Answer:
/ReversedEvenOddString.java
import java.util.Scanner;
public class ReversedEvenOddString {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
String evens = "";
String odds = "";
for(int i = s.length()-1;i>=0;i--){
if(i%2==1){
odds += s.charAt(i);
}
else{
evens += s.charAt(i);
}
}
String res;
if(s.length()%2==1){
res = evens+odds;
}
else{
res = odds+evens;
}
System.out.println(res);
}
}
Answer:
Imaging , Graphics and voice..... requires large computer memory.
Explanation:
