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3 years ago

Convert 192.16.3.1 to a Binary number

1 answer:

5 0

Converting a decimal number into binary would be:

192/2= 96 remainder=0
96/2= 48 remainder=0
48/2=24 remainder=0
24/2=12 remainder=0
12/2=6 remainder=0
6/2=3 remainder=0
3/2=1 remainder=1
1/2= 0 remainder=1
The binary number would be: 11 00 00 00

For 16
16/2=8 remainder=0
8/2=4 remainder=0
4/2=2 remainder=0
2/2=1 remainder=0
1/2= 0 remainder=1
The binary would be: 00 01 00 00

For 3
3/2=1 remainder=1
1/2= 0 remainder=1
The binary would be: 00 00 00 11

For 1
1/2= 0 remainder=1
The binary would be: 00 00 00 01

The binary number would be:
11000000.00010000.00000011.00000001

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Wiki is the correct answer

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3 years ago

Read 2 more answers

The scope of a variable declared outside of any function is:

Marta_Voda [28]

Answer:

a) Global

Explanation:

The scope of a variable declared outside of any function is Global.

Let us consider an example:

int g;

int add(int a,int b){

return a+b;

}

int subtract(int a,int b){

return a-b;

}

Here the variable g is defined outside any function and is accessible anywhere within the program. This is a global variable.

Variables defined within each function - a,b on the other hand have a local scope are are visible only within their respective function bodies.

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3 years ago

To view paragraph marks, click on the ______ tab, in the paragraph group, click show/hide

sergejj [24]

Answer:

Home

Explanation:

Thank Quizlet, lol!

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2 years ago

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago

You should see the following code in your programming

Karo-lina-s [1.5K]

Answer:

import simplegui

import random

def draw_handler(canvas):

for x in range(1000):

colorList = ["Yellow", "Red", "Purple", "White", "Green", "Blue", "Pink", "Orange"]

c = random.choice(colorList)

x = random.randint(1,600)

y = random.randint(1,600)

canvas.draw_point([x, y], c)

frame = simplegui.create_frame('Testing', 600, 600)

frame.set_canvas_background("Black")

frame.set_draw_handler(draw_handler)

frame.start()

Explanation:

I used a for loop, setting my range to 1000 which is how you create exactly 1000 points. Next, I defined my color array, my x randint value, and my y randint value. I set both the x and y randint values to 1 - 600 since the frame is 600x600. The rest is pretty self explanatory.

4 0

2 years ago