Answer:
b
Step-by-step explanation:
second option 400/3
Answer:
-1
Step-by-step explanation:
-7/10+7/15+1/-20+-9/10+11/15+11/-20
= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20
= -16/10 + 18/15 + 12/-20
= -8/5 + 6/5 + -3/5
= (-8+6-3)/5
= -5/5
= -1
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
Angle Addition Postulate
Step-by-step explanation:
Given:

Prove:

Proof:
1.
- Angle Addition Postulate
2.
- given
3.
- given
4.
- Substitution Property of Equality
5.
- Simplify
Monday: t minutes
Tuesday: t + 15 minutes
Wednesday: t minutes
Thursday: t minutes
Friday: t minutes
Monday+Tuesday+Wednesday+Thursday+Friday= minutes ran
t+t+15+t+t+t=
5t+15 minutes