Answer:
a) 74.0353 < u < 74.0367
b) 74.036 < u
Step-by-step explanation:
Given:
- Sample size n = 15
- Standard deviation s.d = 0.0001 in
- Sample mean x_bar = 74.036
Find:
A) Calculate the 99% two-sided confidence interval on the true mean piston diameter.
Solution:
- For 99% CI, We have a = 0.01 , and Z_a/2 = 2.58
------> (x_bar - Z_a/2*s.d / sqrt(n)) < u < (x_bar + Z_a/2*s.d / sqrt(n))
------> (74.036 - 2.58*0.0001 / sqrt(15)) < u < (74.036 + 2.58*0.0001 / sqrt(15))
------> 74.0353 < u < 74.0367
Find:
B) Calculate the 95% one-sided lower confidence interval on the true mean piston diameter.
Solution:
- For 95% lower CI, We have a = 0.05 , and Z_a = 1.645
------> (x_bar - Z_a/2*s.d / sqrt(n)) < u
------> (74.036 - 1.645*0.0001 / sqrt(15)) < u
------> 74.036 < u
m=1 is the answer for that question
Yea what’s deh ummm...question?
Answer:
3/7
Step-by-step explanation:
The number of possible results are;
1, 2 , 3 , 4 , 5, 6 , 7 = 7
odd numbers here are;
1, 3 , 5 and 7
non-odd numbers are 2, 4 and 6
So the section not labeled with an odd number is 3
Hence the probability here is that;
3/7
Answer:
113.
Step-by-step explanation:
119 is divisible by 7.
117 is divisible by 3.
I think it's 113.
If you use your calculator to divide 113 by odd numbers up to 57 you can check if it is prime. You stop at 57 because 57*2 = 114. You need not divide by any number ending in 5 because 113 ends in 3.
I have done this and can't find a quotient that is a whole number so it must be prime (unless I've made a mistake!).