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steposvetlana [31]
3 years ago
8

What is the answer to (x-2)(x+2)

Mathematics
2 answers:
kiruha [24]3 years ago
6 0


Using FOIL (First, Inside, Out, Last), you have to multiply. First: multiply x and x Outside: Multiply x and +2 Inside: Multiply -2 and x Last: Multiply -2 and +2. Finally, add it all together, and you will get x^2-4

Talja [164]3 years ago
3 0
(x - 2)(x + 2)
(x² + 2x - 2x - 4)
x² - 4
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Given the Coordinate R(2, -3) find R'' after the following transformations
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Using translation concepts, it is found that the image of point R after the transformations is given by: (1,-2).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

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The average number of employees that call in sick for the day over the course of a year is 25.
sveta [45]

Answer:

<h3>x¯= 23.8 </h3><h3>μ= 8.2 </h3>

Step-by-step explanation:

<h3>Find the mean. </h3>

 

The mean of a set of numbers is the sum divided by the number of terms.

x¯= <u>25+10+16+39+27+25+32+25+25+22+28+14</u>

                                   11

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x¯ = <u>261.27</u>

            11

<h3>Divide  261.27 by 11 </h3>

x¯= 23.75 18

<h3>Divide. </h3>

x¯= 23.75 18

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

x¯=23.8

<h3>Simplify each value in the list. </h3>

25,10,16,39.27,25,32,25,25,22,28,14

Set up the formula for sample standard deviation. The standard deviation of a set of values is a measure of the spread of its values.

s=  n^∑  i=1    √(<u>xi−xavg</u>)²

                            N-1

             

Set up the formula for standard deviation for this set of numbers.

s= ⎷(25−23.8)²+(10−23.8)²+(16−23.8)²+(39.27−23.8)²+(25−23.8)²+<u>(32−23.8)²+(25−23.8)²+(25−23.8)²+(22−23.8)²+(28−23.8)²+(14−23.8)</u>²

                                       11−1

<h3>Simplify the result. </h3>

 

s= √68.05209

The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

8.2

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