The answer to that is 58,805,595 . hope this helps !!!
7.1, 7.2 ,7.3 ,7.4 ,6.5 ,6.6 ,6.7 ,6.8 ,6.9
90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the giver confidence interval [ 0.3026, 0.3348 ].
Here, we have given:
Number of adults (n) = 2272
Number of adults who believe in UFO (x) = 724
Sample proportion (p) = x/n
p = 724 / 2272
p = 0.3187
now, let q = 1 - p
q = 1 - 0.3187
q = 0.6813
Confidence level → 90%
The 90% confidence interval for population proportion is
![[ p - 1.645\frac{\sqrt{pq} }{\sqrt{n}} ,p + 1.645\frac{\sqrt{pq} }{\sqrt{n}} ]](https://tex.z-dn.net/?f=%5B%20p%20-%201.645%5Cfrac%7B%5Csqrt%7Bpq%7D%20%7D%7B%5Csqrt%7Bn%7D%7D%20%2Cp%20%2B%201.645%5Cfrac%7B%5Csqrt%7Bpq%7D%20%7D%7B%5Csqrt%7Bn%7D%7D%20%5D)
where 1.645 is Zac value at 90% confidence level.
= 0.3187 - 0.0161 = 0.3026
= 0.3187 + 0.0161 = 0.3348
90% confidence interval for the population proportion is
[ 0.3026, 0.3348 ]
Hence, With 90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the giver confidence interval [ 0.3026, 0.3348 ]
Learn more about " Population Proportion " from here: brainly.com/question/15087042
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The answer for this problem is 3.66666666.
Answer:
87.5%
Step-by-step explanation:
There are 376 students in 8th grade at Samuel's school. There are 47 8th graders trying out for football last Thursday.
The number is students not trying out for football last Thursday is calculated as:
376 students - 47 students
= 329 students
The percent of 8th graders that did not try out for football is calculated as:
329 students/376 students × 100
= 329/376 × 100
= 87.5 %