Ashley is ordering 6 bags of cat food from Canada. Each bag has a mass of 7.5kg . To determine the shipping costs, Ashley needs
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Using the normal distribution, it is found that there is a 0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
The probability a randomly selected box has less than the 34 ounces of advertised weight is the <u>p-value of Z when X = 34</u>, hence:
Z = -1.5
Z = -1.5 has a p-value of 0.0668.
0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.
More can be learned about the normal distribution at brainly.com/question/24537145
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