All categories

3 years ago

finding the amplitude, period, asymptotes, reflections, vertical shifts, and phase shifts of trig equations

Mathematics

1 answer:

defon3 years ago

7 0

Answer:

Step-by-step explanation:

hi so i cant read ur question but i would love to help you

You might be interested in

7/12 + 11/12 plssssssssssssssssssssssssssssssssssssssss

krek1111 [17]

Answer:

3/2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please help me

yKpoI14uk [10]

9514 1404 393

Answer:

A) 5x+12 = -12x-12

D) 5x+12 = -5x-12

Step-by-step explanation:

If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.

A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution

B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions

C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions

D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution

6 0

2 years ago

Which is f(6) for the quadratic function graphed? 0 -2 * -0.5 1.5 4

rusak2 [61]

Answer:

Step-by-step explanation:

I'm pretty sure theres a graph to this so....

The given parabolic graph of quadratic function

To find:What is F(6) for the quadratic function

Solution:We have given graph of quadratic function

there is a different value for Y and a different value for X

For f(6)

here X=6, need to find graph of quadratic function

X=6

f(6)=4

Y=4

Your welcome :)

4 0

2 years ago

You pick a marble and spin the spinner. How many outcomes are possible?

grigory [225]

Answer:

4 i think

Step-by-step explanation:

can you go one question to the left i need help

6 0

3 years ago

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

Andrei [34K]

Answer: see below

Step-by-step explanation:

1) Foci is plural for Focus. Since a hyperbola has two focus points, they are referred to as foci. The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

a) does the hyperbola open up or to the right?

b) what is the center (h, k) of the hyperbola?

c) What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1$

(h, k) is the center of the hyperbola
± b/a is the slope of the line of the asymptotes
The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0

3 years ago