1. (x−1)(5x+8)−2x+5
=(x)(5x)+(x)(8)+(−1)(5x)+(−1)(8)+−2x+5
=5x2+8x+−5x+−8+−2x+5
Combine Like Terms:
=5x2+8x+−5x+−8+−2x+5
=(5x2)+(8x+−5x+−2x)+(−8+5)
=5x2 + x + −3
2. (−2+5)(3x+9)
=9x+27
3. 2x+5−8x+12
=2x+5+−8x+12
Combine Like Terms:
=2x+5+−8x+12
=(2x+−8x)+(5+12)
=−6x+17
4. (−x+3)(−5x−2)
=(−x+3)(−5x+−2)
=(−x)(−5x)+(−x)(−2)+(3)(−5x)+(3)(−2)
=5x2+2x−15x−6
=5x2 − 13x − 6
Answer:
K=27
Step-by-step explanation:
3(-21+k)=18
-63+3k=18
3k=18+63
3k=81
K=81/3
K=27
Answer:
The sandwich cost $5.75
Step-by-step explanation:
9 = s + 3.25
-3.25 -3.25
5.75 = s
Answer:
∠ 1 = 109° , ∠ 2 = 29° , ∠ 3 = 71°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180° , then
∠ 1 + 35° + 36° = 180°
∠ 1 + 71° = 180° ( subtract 71° from both sides )
∠ 1 = 109°
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∠ RVU and ∠ 1 are adjacent angles on a straight line and sum to 180° , then
∠ RVU + ∠ 1 = 180°
∠ RVU + 109° = 180° ( subtract 109° from both sides )
∠ RVU = 71°
In Δ RVU
∠ 2 + 80° + 71° = 180° ( sum of angles in triangle )
∠ 2 + 151° = 180° ( subtract 151° from both sides )
∠ 2 = 29°
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∠ 3 and ∠ RVU are vertically opposite angles and are congruent , then
∠ 3 = 71°
F(x) = x^2 + 2x -1
Domain all real number
Range: all real numbers equal or greater than -2.
To find the range you need to find the vertex of the parabole, which is (-1,-2) and use the fact that, given that the coefficient of x^2 is positive, the funcion open upwards (which means that the vertex is a global minimum).
To find the vertex you use the quadratic formula to find the roots and then the x-coordinate of the vertex is in the middle of the two roots.
