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Valentin [98]
3 years ago
8

the utilities bill for the Miller's' house in April was $132. forty two percent of the bill was for gas, and the rest was for el

ectricity. How much did the millers pay for gas, and how much did they pay for electricity
Mathematics
2 answers:
Ostrovityanka [42]3 years ago
6 0
132 × 42% = 132 × 42/100 = 132 × 0.42 = 55.44 $ for gas

132 $ - 55.44 $ = 76.56 $ for electricity

Lynna [10]3 years ago
4 0
Hey You!

132*42% = 55.44

132 - 55.44 = 76.56

So, the Millers paid $55.44 for gas and $76.56 for electricity.
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Answer:

6x+20

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Step-by-step explanation:

If f(x)=6x+2 and you are asked to find f(x+3), then you just replace all the x's in f(x)=6x+2 with (x+3).

Doing this gives you:

f(x)=6x+2        with new input (x+3) in place of out input (x)

f(x+3)=6(x+3)+2

f(x+3)=6x+18+2

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
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