X = 4 ; x = 3 + i ; x = 3 - i
(If you get a zero that is adding or subtracting, you always need to write it twice but change the sign do they cancel out)
f(x) = (x-4)(x-3-i)(x-3+i)
Distributing the last two parenthesis first is always the best way to start off
(x-3-i)(x-3+i) has (x-3) in common so it can be separated to
(x-3)^2 + (-i)(+i)
(x^2 - 6x + 9) ; (-i)(+i) is always +1
(x^2 - 6x + 9) + 1
(x^2 - 6x + 10)
Now multiply this with (x-4)
x^3 - 6x^2 + 10x
- 4x^2 + 24x - 40
x^3 - 10x^2 + 34x - 40 = f(x)
Answer:
The area of the figure is equal to 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of the figure is equal to the area of a square plus the area of a triangle
<u>Find the area of the square</u>
The area of square is equal to
<u>Find the area of the triangle</u>
The area of the triangle is equal to
therefore
The area of the figure is equal to
I did the math and <span>x=116</span>
F represents A special relationship where each input has a single output. It is often written as "f(x)" where x is the input value.
0.7 and -0.4 is you wanted them as decimals
