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storchak [24]
3 years ago
8

Pls answer the first one

Mathematics
1 answer:
Crank3 years ago
7 0

Answer:

729

Step-by-step explanation:

switch anything with a negative exponent to the opposite side of the fraction bar

81 x 4 x 3^7 x 10^3/5^3 x 6^5

708588/972 = 729


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Help me again pls :D sorry for the bother
matrenka [14]

Answer:

A

Step-by-step explanation:

2x2.5x3= 15

2x2.5x4.5=22.5

2.5x3x4=30

2.5x2x4=20

6 0
3 years ago
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Answer:

You already made an acc-

Step-by-step explanation:

Wdym?

4 0
3 years ago
Everyone has the right to influence tax policy.
Ira Lisetskai [31]
Whats the question??
5 0
3 years ago
20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
The terminal point of Dis ( 1/2,3/2). What is cos 0?
nydimaria [60]

Answer:

<em>(c). </em>\frac{1}{2}<em> </em>

Step-by-step explanation:

The <u><em>cosine</em></u> is the <em>"x" coordinate</em> of the terminal point on the unit circle.

Thus the answer is <em>(c). </em>\frac{1}{2}

5 0
3 years ago
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