Answer:
8
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8
p2 - 2p + 8p - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (p-2)
Add up the last 2 terms, pulling out common factors :
8 • (p-2)
Step-5 : Add up the four terms of step 4 :
(p+8) • (p-2)
Which is the desired factorization
Answer:
Tn = -4n²+40n+36
Step-by-step explanation:
A general quadratic sequence, Tn = an²+bn+c, where n is the term of the sequence.
So, when n = 1, Tn = 72, which means T1 = a+b+c=72.
when n = 2, Tn = 100, which means T2= 4a+2b+c = 100
when n = 3, Tn = 132, which means T3 = 9a+3b+c = 132.
Now, use a calcaulatot to solve the 3 variable simultaneous equation. According to my calculator, a = -4, b = 40, c = 36.
Hence, you a, b, and c in the Tn equation given above.
Therefore, <em>Tn = -4n²+40n+36</em>
I think the answer is the second one, Tessa wasn't sure how far she would swim during the first class. She would swim 3 laps during the second class. The question is confusing, because the equation s+3 is supposed to be the DISTANCE she swam in 2 classes. The problem didn't specify that distance equals laps, but I think the answer is correct
