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4 years ago

The following table represents amount of vanadium-49 remaining in a sample of rock

2 answers:

7 0

This is an example of an exponential decay problem.

The basic format of the equation is: $y=ab x^{123} x$

In this problem, the starting amount is 100. The rate is 0.5 because it is being cut in half every 330 days.

irina [24]4 years ago

6 0

Exoponential decay function

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The temperature at 5:30 A.M. was recorded as 7 degrees below zero on the Fahrenheit scale. Write the temperature using a signed

Svet_ta [14]

Answer:

mhhm yea this is very questioned questioned

Step-by-step explanation:

yea mhm

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3 years ago

3. Use each number line to show a different way to count from $580 to $994

Amiraneli [1.4K]

What are the number lines though?

Give more info.

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3 years ago

How can 2/3 + 3/12 be rewritten so they can be added?

Drupady [299]

well, you can multiply the values to where they are equivalent, so multiply 2/3 by 4 ( both numbers ) so you get 8/12 and 3/12, so, just in case you want POST added, the answer to 2/3 ( 8/12 ) + 3/12 = is 11/12!

Hope this helps, if not, comment below please!!!

6 0

3 years ago

Read 2 more answers

What is the greatest common factor of 18 and 45

lisov135 [29]

The prime factorization of 18 is: 2 x 3 x 3.
The prime factorization of 45 is: 3 x 3 x 5.
The prime factors and multiplicities 18 and 45 have in common are: 3 x 3.
3 x 3 is the gcf of 18 and 45.
gcf(18,45) = 9.

5 0

3 years ago

The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind

Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 21.3, \sigma = 3.9, n = 40, s = \frac{3.9}{\sqrt{40}} = 0.6166$

Treating this as a random sample, at what mean oil-change time would there be a 10% chance of being at or below?

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$-1.28 = \frac{X - 21.3}{0.6166}$

$X - 21.3 = -1.28*0.6166$

$X = 20.51$

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

6 0

3 years ago