Cot= cos/sin
<=> cot= [(✔️13^2-5^2)/13]/(5/13)
<=> cot= (12/13)/(5/13)
<=> cot= 12/5
Answer:
y = 4 sin( 0.5t - ) - 2
y = a sin ( 2t - ) + 2
Step-by-step explanation:
In the first question,
amplitude = 4
Period =
phase shift =
Vertical shift = -2
Angular velocity , w =
Here, w = = 0.5
The general equation of a wave is
y = a sin( wt + ∅ )
Putting above values in the equation,
y = 4 sin( 0.5t - ) - 2
In the second question,
Amplitude is not given so we will take it as a.
time period =
w = 2
Phase shift =
Vertical shift = 2
The equation is
y = a sin ( 2t - ) + 2
I Think the answer is 31 because 20-5 is 15 so 36-5 is 31
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
45/60= .75 miles each minute
45x2= 90 miles in 2 hours
.75×20=15 miles in 20 min
90+15=105 miles in 2 hours n 20 min