There are two solutions to this question, one is positive and the other is negative:
Answer:
The area of the sidewalk is 144.44 m².
The 2-m wide walk adds 4 m to the diameter, making it 21+4=25.
Since the radius is half the diameter, r = 25/2 = 12.5.
The area of the entire bed with walkway is 3.14(12.5)² = 490.625 m².
The diameter of the bed is 21, so the radius is 21/2 = 10.5.
The area of just the flower bed is 3.14(10.5)² = 346.185.
The difference between the two is 490.625-346.185 = 144.44 m². This is the area of the walkway.
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Oh gosh i wish i knew how to do that what grade are u in cause i remember having that last year but dont remember.
L=16
W=21
Set up a systems of equations:
x=length
y=width
xy=336
x+5=y
Use substitution to solve:
x(x+5)=336
x^2+5x=336
Solve using factoring:
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21
Since length can't be negative, l=16
To find width, plug length into the first equation:
(16)y=336
y=21
So...
L=16
<span>W=21</span>
Answer:
37
Step-by-step explanation:
