4x + 3y = 5...(1)
2x + 3y = 1...(2)
(2)*2:
4x+6y=2...(3)
(1)-(3):
4x+3y-(4x+6y)=5-2
4x+3y-4x-6y=3
-3y=3
y=-1
By sub. y=-1 in (2), we have
2x+3(-1)=1
2x-3=1
2x=4
x=2
The solution is x=2,y=-1
0.4 is the divisor, or whichever number is under the fraction. This is because the denominator of any fraction is always the divisor of the numerator of the fraction.
Answer:
The two page numbers are 78 and 79.
Step-by-step explanation:
Let's take the page numbers are x and x + 1
.
The produce of the page numbers is 6162
so, x(x + 1) = 6162

Here we have to use the quadratic formula to solve for x.
The quadratic formula, x = 
Here a =1, b = 1 and c = -6162
Plugging in the value of a, b and c in the above formula, we get
x = [-1 ± 157] ÷ 2
Let's take the positive value alone since the page number cannot be negative.
x = [-1 + 157]
÷2
x = 78
The next page number x + 1 = 78 + 1 = 79
Therefore, the two page numbers are 78 and 79.
Answer:
the answer is c
Step-by-step explanation:
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