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Korolek [52]
3 years ago
9

Help need answered ASAP!

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0

1 3/4 because the comments below moi dudes ;)

Lyrx [107]3 years ago
6 0

Answer:

Option B is correct

1\frac{3}{4} miles will Lucas walk if he takes route B

Step-by-step explanation:

As per the statement:

There are two routes Lucas can take to walk to school.

Route A is 2\frac{1}{8} = \frac{17}{8} miles and is 3/8 mile longer than route B

here, b is the length of route B.

The equation we get;

b+\frac{3}{8} = 2\frac{1}{8}

⇒b+\frac{3}{8} = \frac{17}{8}

Subtract \frac{3}{8} from both sides we have;

⇒b = \frac{17}{8} -\frac{3}{8} = \frac{17-3}{8} = \frac{14}{8} = \frac{7}{4} = 1\frac{3}{4}

Therefore, 1\frac{3}{4} miles will Lucas walk if he takes route B

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Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr
Minchanka [31]

Answer:

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  The margin of error is the range of values below and above the sample statistic in a confidence interval.  Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  [tex]p_1 represent the real population proportion for 1

\hat p_1 =0.768 represent the estimated proportion for 1

n_1=92 is the sample size required for 1

p_2 represent the real population proportion for 2

\hat p_2 =0.646 represent the estimated proportion for 2

n_2=95 is the sample size required for 2

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}  

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

ME= \frac{0.2753-(-0.0313)}{2}=0.1533

And we know that the margin of erro is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}

We have all the values except the value for z_{\alpha/2}

So we can find it like this:

0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}

And solving for z_{\alpha/2} we got:

z_{\alpha/2}=2.326

And we can find the value for \alpha/2 with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98 or 98%

7 0
3 years ago
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Nookie1986 [14]

this picture would help you man stay strong

4 0
3 years ago
Ariana and Sean went out to dinner with their parents. The price paid for their meal was $75.60 before taxes. The sales tax rate
KengaRu [80]

Answer: $97.524

Step-by-step explanation:

First let's calculate the price after the tax rate:

converting 7.50% to a decimal = 0.0750 now we multiply the sales tax by 75.60 which equals $5.67 add it to 75.60 = 81.27 (our new total)

Now let's calculate the tip. Again turning 20% to a decimal = .20 now multiplying by 81.27 = 16.254. Adding 16.254 to 81.27 we get our final answer: $97.524

6 0
4 years ago
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
3 years ago
A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott
jeka57 [31]

Answer:

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Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } cm^{2}

This area is equal to 125 cm^{2} as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ a^{2} - 18 a +80 -125 =0

⇒ a^{2} - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a > 4.

Thus the required answer is 15 cm.

7 0
3 years ago
Read 2 more answers
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