Answer and Step-by-step explanation:
The computation is shown below:
Let us assume that
Spam Email be S
And, test spam positive be T
Given that
P(S) = 0.3
Now based on the above information, the probabilities are as follows
i. P(Spam Email) is
= P(S)
= 0.3
= 1 - 0.3
= 0.7
ii. 
= 0.8906
iii. 
= 0.0221
We simply applied the above formulas so that the each part could come
Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be
11/33 x 100=33.333333...
About 33.333 of the voters voted for candidate a.
Let one odd integer = x
other odd integer = x +2
Sum = x + x+2 = -44
=> 2x + 2 = -44
=> 2x = -44 -2 = -46
=> x = -46/2 = -23
x+2 = -23 + 2 = -21
Integers are -23 and -21
Answer:
ok so we can turn both of these into equations
Bob: 112.96 divided by 138=0.81855072463
so about 82 cents per mile
Carl: 142.78 divided by 209=0.68315789473
so about 68 cents per mile
so ya i am a little confused but heres what i got
(24 × 17 × 130\2)
24 × 17 = 408 x 130 = 53,040 / 2 = 26,520
So the volume of this box is
C= 26,520 cm^3
