The function (119x + 171) represents the amount, in dollars. Lionel will save 409 $ if he uses Quality Electric for a repair needing 2 hours of labor.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
The system of equations are;
p(x) = 68x + 81.
q(x) = 51x + 90.
So,
p(x) + q(x) = 68x + 81 + 51x + 90
p(x) + q(x) = 119x + 171
The function (119x + 171) represents the amount, in dollars, Lionel will save by having Quality Electric handle an x-hour repair instead of Phil’s Appliances.
p(x) + q(x) = 119x + 171
x= 2 hours
p(x) + q(x) = 119 (2) + 171
p(x) + q(x) = 409
Lionel will save 409 $ if he uses Quality Electric for a repair needing 2 hours of labor.
Learn more about equations here;
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Inter portal range of 4th period box plot is higher than the 2nd period of box plot. The 4th period class should get the reward.
<h3>
What is box plot?</h3>
Box plot is the way of representation of data which gives the graphical image of the data set to understand better.
The minimum and the maximum values in the box plot is plotted at the end points.
Given information-
Box plot labeled 2nd period with min at 77, Q1 at 78, median at 89, Q3 at 92, max at 100.
Box plot labeled 4th period with min at 72, Q1 at 82.5, median at 89, Q3 at 96, max at 97. 5.
From the box plot we can see the points as,
- The maximum score of the 2nd period class is 77 and the 4th period class is 72, but this does not show the better performance of the class.
- The maximum score of the 2nd period class is 100 and the 4th period class is 97.5, but this does not show the better performance of the class.
- Median for both the class is same which is 89.
- The inter portal range of the box plot of 4th period is higher than the 2nd period box plot. Thus 4th period class performed better.
Hence, the 4th period class should get the reward. Though the medians are the same, the first and third quadrilles are higher, so the students did better on average than in the 2nd period class.
Learn more about the box plot here;
brainly.com/question/14277132
<h2>
Explanation:</h2><h3>Part A.</h3>
The boundary lines of both inequalities will be dashed, because neither includes the "or equal to" case.
The first inequality solution area is bounded by a line with slope +5 and y-intercept +5. The solution area is above the line (y is greater than ...). Since the line rises steeply, the solution area looks to be to the left of the line. (It is shaded red on the attached graph.)
The second inequality solution area is bounded by a line with slope -1/2 and y-intercept +1. The solution area for this inequality is also above the line.
The solution area is where the two solution spaces overlap, in the quadrant to the upper left of the point where the lines intersect.
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<h3>Part B.</h3>
The graph shows the point (-2, 5) to be in the solution space.
We can show this point satisfies both inequalities.
- 5 > 5(-2)+5 ⇒ 5 > -5 . . . true
- 5 > (-1/2)(-2) +1 ⇒ 5 > 2 . . . true
Answer:
Ok ill help
Step-by-step explanation:
Answer:
Ok
Step-by-step explanation:
do u mean into bracket 61/4 raised to the power of 4???
