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Leviafan [203]
3 years ago
14

Consider a sampling distribution with p equals 0.12 and samples of size n each. Using the appropriate​ formulas, find the mean a

nd the standard deviation of the sampling distribution of the sample proportion.
(a) For a random sample of size n equals 5000.
(b) For a random sample of size n equals 1000.
(c) For a random sample of size n equals 500.
Mathematics
1 answer:
Mandarinka [93]3 years ago
8 0
<h2>Answer with explanation:</h2>

Consider a sampling distribution with p equals 0.12 and samples of size n each.

Then, formula for mean = p

Formula for standard deviation= \sqrt{\dfrac{p(1-p)}{n}}

(a) For a random sample of size n equals 5000.

Mean = 0.12

Standard deviation= \sqrt{\dfrac{0.12(1-0.12)}{5000}}

\\\\0.00459565011723\approx0.0046

(b) For a random sample of size n equals 1000.

Mean = 0.12

Standard deviation= \sqrt{\dfrac{0.12(1-0.12)}{1000}}

\\\\=0.0102761860629\approx0.0103

(c) For a random sample of size n equals 500.

Mean = 0.12

Standard deviation= \sqrt{\dfrac{0.12(1-0.12)}{500}}

\\\\=0.0145327216997\approx0.0145

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