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2 years ago

Find the area. Will mark brainliest.

Mathematics

1 answer:

tino4ka555 [31]2 years ago

8 0

Answer:

216

Step-by-step explanation:

I think that it is 216 because if you add 18 and 10 you get 28 then multiply 28 by 12 then you get 336. Then you will find the area of the unshaded part which is 120. Then you will subtract 120 from 336 to get 216.

Hope this helps

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Last year, 20,820 people attended a kite festival. This year, 19779 people attended it. If attendance continues to decrease by t

ICE Princess25 [194]

Well you start by dividing 19779 by 20820 to see the percent of people compared to last year (it being 95%). Then you take 19,779 and multiply it by the same percentage, or 0.95. That means that there should be 18790 (it's technically 18790.1 but since that's people you round to the nearest whole number).

4 0

2 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

∴ we have used u-solve (u-substitution) to find the indefinite integral.

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Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0

1 year ago

Please please help me

docker41 [41]

Ur missing numbers are -2, 6, and 36

Since the center point is (-2,6), the numbers are reversed in the equation to: (x+2) or(x- -2) and (y-6)

The radius is 6 units so u square it to get 36

7 0

2 years ago

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ivolga24 [154]

Answer:

true

Step-by-step explanation:

true

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miskamm [114]

Answer:

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Step-by-step explanation:

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2 years ago