Multiply all terms by x and cancel:<span><span>6+<span>2x</span></span>=<span><span>3x</span>4</span></span><span><span><span>2x</span>+6</span>=<span><span>34</span>x</span></span>(Simplify both sides of the equation)<span><span><span><span>2x</span>+6</span>−<span><span>34</span>x</span></span>=<span><span><span>34</span>x</span>−<span><span>34</span>x</span></span></span>(Subtract 3/4x from both sides)<span><span><span><span>54</span>x</span>+6</span>=0</span><span><span><span><span><span>54</span>x</span>+6</span>−6</span>=<span>0−6</span></span>(Subtract 6 from both sides)<span><span><span>54</span>x</span>=<span>−6</span></span><span><span><span>(<span>45</span>)</span>*<span>(<span><span>54</span>x</span>)</span></span>=<span><span>(<span>45</span>)</span>*<span>(<span>−6</span>)</span></span></span>(Multiply both sides by 4/5)<span>x=<span><span>−24</span>5</span></span>Check answers. (Plug them in to make sure they work.)<span>x=<span><span><span>−24</span>5</span></span></span>
Answer:
Step-by-step explanation: let the first number be x and the second number be y
according to the condition given
x+y=21
3x-y=43
using elimination method
3x+3y=63
3x-y=43
subtacting both the equations
4y=20
y=20/4
y=5
substituting value of y in eq 1
x+5=21
x=21-5
x=16
therefore x=16 and y=5
the two numbers are 16 and 5
Answer:
Q3 = 34
Q1 = 24.5
Step-by-step explanation:
Q1 is the middle value in the first half of the data set.
Q3 is the middle value in the second half of the data set.
put the numbers in order
find the median
Answer:
h_max = 324.09 ft
Step-by-step explanation:
The correct equation is;
h = 245t - 16t²
We are told that as the rocket descends, it deploys
a recovery parachute when it reaches 325 feet above the ground.
Thus;
245t - 16t² = 325
Thus;
16t² - 245t + 325 = 0
Using quadratic formula, we have the roots as;
t = 1.47s or 13.85s
We will pick the higher value.
Thus;
Maximum height will occur at t = 13.85 s
Thus, plugging in 13.85 for t into h = 245t - 16t², we have;
h_max = 245(13.85) - 16(13.85)²
h_max = 324.09 ft