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Anika [276]
2 years ago
7

Study each equation, then solve. 18) 5 + r = 6 - r

Mathematics
1 answer:
Keith_Richards [23]2 years ago
5 0

Answer:

5+r=6-r

-5 -5

r=1-r

+r +r

2r=1

÷2 ÷2

r=1/2

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Points a,b and c are collinear and in that order. If AC=3x+3, AB=-1+2x, and Bc=11, find x and AC
zimovet [89]

The answers are:

AC = AB + BC

3x+3 = -1+2x+11

3x-2x = -1-3+11

x = 7


AC = 3x+3                   x = 7

AC = 3x7+3

AC = 24


Hope it helps!


4 0
2 years ago
Bradley paid $33.53 for 7 gallons of milk. What is the price per milk gallon
katrin2010 [14]

Answer:

The Answer is 4.79

Step-by-step explanation:

All you have to do Divide 33.53 by 7 then you would get 4.79

I say divide because they want to know how much it one gallon of milk costs  So that is  why you have to divide

Hope I Helped! :3

3 0
3 years ago
Read 2 more answers
5/9+1/9 in simplest form. Explain.
Lana71 [14]

Answer:

2/3

Step-by-step explanation:

5/9 + 1/9

= 6/9

= 2/3 in simplest form

8 0
2 years ago
Evaluate:<br> (-4x+6) + (x-5)
Lady bird [3.3K]

Answer:

-3x+1

Step-by-step explanation:

8 0
3 years ago
Find the exact value of csc(-1860).
Alex787 [66]
Now, there are 360° in a circle, how many times does 360° go into 1860°?

well, let's check that,   \bf \cfrac{1860}{360}\implies \cfrac{31}{6}\implies 5\frac{1}{6}\implies 5+\frac{1}{6}

now, this is a negative angle, so it's going clockwise, like a clock moves, so it goes around the circle clockwise 5 times fully, and then it goes 1/6 extra.

well, we know 360° is in a circle, how many degrees in 1/6 of 360°?  well, is just 360/6 or their product, and that's just 60°.

so -1860, is an angle that goes clockwise, negative, 5 times fully, then goes an extra 60° passed.

5 times fully will land you back at the 0 location, if you move further down 60° clockwise, that'll land you on the IV quadrant, with an angle of -60°.

therefore, the csc(-1860°) is the same as the angle of csc(-60°), which is the same as the csc(360° - 60°) or csc(300°).

\bf csc(300^o)\implies \cfrac{1}{sin(300^o)}\implies \cfrac{1}{-\frac{\sqrt{3}}{2}}\implies -\cfrac{2}{\sqrt{3}}&#10;\\\\\\&#10;\textit{and if we rationalize the denominator}\qquad -\cfrac{2\sqrt{3}}{3}
3 0
3 years ago
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