Answer:
Option (B). Perimeter of the quadrilateral ABCD= 14.6 units
Step-by-step explanation:
From the figure attached,
Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).
Length of AB = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D)
= ![\sqrt{(3-1)^2+(5-3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%283-1%29%5E2%2B%285-3%29%5E2%7D)
= ![\sqrt{8}](https://tex.z-dn.net/?f=%5Csqrt%7B8%7D)
= 2.83 units
Length of AD = ![\sqrt{(3-5)^2+(5-3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%283-5%29%5E2%2B%285-3%29%5E2%7D)
= ![\sqrt{8}](https://tex.z-dn.net/?f=%5Csqrt%7B8%7D)
= 2.83 units
Length of BC = ![\sqrt{(1-3)^2+(3+1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%281-3%29%5E2%2B%283%2B1%29%5E2%7D)
= ![\sqrt{20}](https://tex.z-dn.net/?f=%5Csqrt%7B20%7D)
= 4.47 units
Length of DC = ![\sqrt{(5-3)^2+(3+1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-3%29%5E2%2B%283%2B1%29%5E2%7D)
= ![\sqrt{20}](https://tex.z-dn.net/?f=%5Csqrt%7B20%7D)
= 4.47 units
Perimeter of the quadrilateral = AB + AD + DC + BC
= 2.83 + 2.83 + 4.47 + 4.47
= 14.6 units
Option (B) is the answer.
<em>Answer:</em>
<em>38%</em>
<em>Step-by-step explanation:</em>
<em>60 percent girls</em>
<em>50 percent of girls walk</em>
<em>50 percent take the bus</em>
<em></em>
<em>40 percent boys</em>
<em>20 percent walk</em>
<em>80 percent take the bus</em>
<em></em>
<em>If there are 100 people in the school</em>
<em>60 girls</em>
<em>30 girls take the bus</em>
<em></em>
<em>40 boys</em>
<em>8 boys walk</em>
<em></em>
<em>8+30=38</em>
<em>38% of the people walk to school</em>
Answer:
There are a total of possible 1820 results.
Step-by-step explanation:
Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:
![Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455](https://tex.z-dn.net/?f=Boys%20%3D%20%5Cfrac%7B15%21%7D%7B3%21%2815%20-%203%29%21%7D%20%3D%20%5Cfrac%7B15%21%7D%7B3%2112%21%7D%20%3D%20%5Cfrac%7B15%2A14%2A13%2A12%21%7D%7B3%2112%21%7D%5C%5CBoys%20%3D%20%5Cfrac%7B15%2A14%2A13%7D%7B3%2A2%2A1%7D%5C%5CBoys%20%3D%20%5Cfrac%7B15%2A14%2A13%7D%7B3%2A2%2A1%7D%5C%5CBoys%20%3D%20455)
![Girls = \frac{4!}{3!*(4 - 3)!}\\Girls = \frac{4*3!}{3!}\\Girls = 4](https://tex.z-dn.net/?f=Girls%20%3D%20%5Cfrac%7B4%21%7D%7B3%21%2A%284%20-%203%29%21%7D%5C%5CGirls%20%3D%20%5Cfrac%7B4%2A3%21%7D%7B3%21%7D%5C%5CGirls%20%3D%204)
Total number of possible results:
![results = 4*455\\results = 1820](https://tex.z-dn.net/?f=results%20%3D%204%2A455%5C%5Cresults%20%3D%201820)
It would be 6x + 6y as the final expansion
Answer:
it can be times a number tjatgoes into 8