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dolphi86 [110]
2 years ago
14

If ALTU ASBP then TU = [?] Enter the letters that belong in the green box. Enter

Mathematics
1 answer:
finlep [7]2 years ago
7 0

Answer:

BP

Step-by-step explanation:

the letters are congruent in order, so the last 2 letters of both sides are congruent

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One of the valves on the Hoover Dam releases 40,000 gallons per second. What is the rate in gallons per minute
postnew [5]

There are 60 seconds in a minute. there are 40,000 in a second. That means we have to multiply that by 60.

60*40,000= 2,400,000

The answer is 2,400,000 gallons per minute.

4 0
2 years ago
(((QUICK QUESTION-WILL GIVE BRAINLYEST)))
svetoff [14.1K]

Given:

Point (7,12) is rotated 1260° counterclockwise about the origin.

To find:

The  x-coordinate of the point after this rotation.

Solution:

If a point is rotated 360 degrees then its coordinates remains unchanged.

If a point is rotated 180 counterclockwise about the origin degrees, then

(x,y)\to (-x,-y)

We know that,

1260^\circ=1080^\circ+180^\circ

1260^\circ=3\times 360^\circ+180^\circ

After 3\times 360^\circ rotation the coordinates of points remains same, i.e., (7,12). So, after that (7,12) is rotated 180° counterclockwise about the origin.

(7,12)\to (-7,-12)

The point (7,12) becomes (-7,-12) after rotation of  1260° counterclockwise about the origin.

Therefore, the x-coordinate of the required point is -7.

3 0
3 years ago
The circumference for a circle that has a radius or 7 inches is
lidiya [134]
Circumference
C=2πr
C=2(3.14)(7)
C=(3.14)(14)
C=43.96
7 0
3 years ago
There is 3/4 of pizza leftover from the night before . how many 1/8 portions are there
serg [7]
We want to know how many 1/8's are in 3/4, so we divide.

\sf\dfrac{3}{4}\div\dfrac{1}{8}

Flip the 2nd fraction and multiply:

\sf\dfrac{3}{4}\times\dfrac{8}{1}

Multiply the numerators and denominators together:

\sf\dfrac{3\times8}{4\times1}\rightarrow\dfrac{24}{4}

Divide:

\boxed{\sf6}
3 0
3 years ago
Read 2 more answers
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
2 years ago
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