The slope intercept form of the equation of line will be;
The equation of line passes through the points (0, -1) and (0.5, 0) is,
⇒ y = 2x - 1
And, The equation of line passes through the points (0, -4) and (5, 0).
⇒ y = 0.8x - 4
What is Equation of line?
The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
Two points on the line are (0, -1) and (0.5, 0).
And, Another coordinate plane, a line goes through (0,- 4) and (5, 0).
Now,
Since, The equation of line passes through the points (0, -1) and (0.5, 0).
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (0 - (-1)) / (0.5 - 0)
m = 1 / 0.5
m = 2
Thus, The equation of line with slope 2 is,
⇒ y - (-1) = 2 (x - 0)
⇒ y + 1 = 2x
⇒ y = 2x - 1
And,
Since, The equation of line passes through the points (0, -4) and (5, 0).
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (0 - (-4)) / (5 - 0)
m = 4 / 5
m = 0.8
Thus, The equation of line with slope 0.8 is,
⇒ y - (-4) = 0.8 (x - 0)
⇒ y + 4 = 0.8x
⇒ y = 0.8x - 4
Thus, The slope intercept form of the equation of line will be;
The equation of line passes through the points (0, -1) and (0.5, 0) is,
⇒ y = 2x - 1
And, The equation of line passes through the points (0, -4) and (5, 0).
⇒ y = 0.8x - 4
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