Volume of a cone, V = πr^2h/3

r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum

Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2

Therefore, minimum amount of paper required is 92.95 cm^2

4 0

3 years ago

Plz I need help with this test that I have due today!!!!!

Oduvanchick [21]

Answer:

Step-by-step explanation:

Hopefully this helps.

4 0

3 years ago

What is the length of MN?

sleet_krkn [62]

Answer:

Here you go ! Hope it helps.

5 0

3 years ago

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Find the infinite sum of 10,5,2.5,1.25...

____ [38]

Notice this is a geometric progression since each number multiplied by some factor equals the next number in the sequence, in this case,

$10 \times r = 5 \Rightarrow r=0.5$

Then by applying the formula for sum to infinity of a geometric progression,
$S_\infty = \frac{a}{1-r} = \frac{10}{1-0.5} = 20$

3 0

3 years ago

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